Optimal. Leaf size=176 \[ \frac{a^3 (38 B+45 C) \sin (c+d x)}{15 d}+\frac{a^3 (43 B+45 C) \sin (c+d x) \cos ^2(c+d x)}{60 d}+\frac{a^3 (13 B+15 C) \sin (c+d x) \cos (c+d x)}{8 d}+\frac{(7 B+5 C) \sin (c+d x) \cos ^3(c+d x) \left (a^3 \sec (c+d x)+a^3\right )}{20 d}+\frac{1}{8} a^3 x (13 B+15 C)+\frac{a B \sin (c+d x) \cos ^4(c+d x) (a \sec (c+d x)+a)^2}{5 d} \]
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Rubi [A] time = 0.446618, antiderivative size = 176, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 40, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.175, Rules used = {4072, 4017, 3996, 3787, 2635, 8, 2637} \[ \frac{a^3 (38 B+45 C) \sin (c+d x)}{15 d}+\frac{a^3 (43 B+45 C) \sin (c+d x) \cos ^2(c+d x)}{60 d}+\frac{a^3 (13 B+15 C) \sin (c+d x) \cos (c+d x)}{8 d}+\frac{(7 B+5 C) \sin (c+d x) \cos ^3(c+d x) \left (a^3 \sec (c+d x)+a^3\right )}{20 d}+\frac{1}{8} a^3 x (13 B+15 C)+\frac{a B \sin (c+d x) \cos ^4(c+d x) (a \sec (c+d x)+a)^2}{5 d} \]
Antiderivative was successfully verified.
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Rule 4072
Rule 4017
Rule 3996
Rule 3787
Rule 2635
Rule 8
Rule 2637
Rubi steps
\begin{align*} \int \cos ^6(c+d x) (a+a \sec (c+d x))^3 \left (B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx &=\int \cos ^5(c+d x) (a+a \sec (c+d x))^3 (B+C \sec (c+d x)) \, dx\\ &=\frac{a B \cos ^4(c+d x) (a+a \sec (c+d x))^2 \sin (c+d x)}{5 d}+\frac{1}{5} \int \cos ^4(c+d x) (a+a \sec (c+d x))^2 (a (7 B+5 C)+a (2 B+5 C) \sec (c+d x)) \, dx\\ &=\frac{a B \cos ^4(c+d x) (a+a \sec (c+d x))^2 \sin (c+d x)}{5 d}+\frac{(7 B+5 C) \cos ^3(c+d x) \left (a^3+a^3 \sec (c+d x)\right ) \sin (c+d x)}{20 d}+\frac{1}{20} \int \cos ^3(c+d x) (a+a \sec (c+d x)) \left (a^2 (43 B+45 C)+2 a^2 (11 B+15 C) \sec (c+d x)\right ) \, dx\\ &=\frac{a^3 (43 B+45 C) \cos ^2(c+d x) \sin (c+d x)}{60 d}+\frac{a B \cos ^4(c+d x) (a+a \sec (c+d x))^2 \sin (c+d x)}{5 d}+\frac{(7 B+5 C) \cos ^3(c+d x) \left (a^3+a^3 \sec (c+d x)\right ) \sin (c+d x)}{20 d}-\frac{1}{60} \int \cos ^2(c+d x) \left (-15 a^3 (13 B+15 C)-4 a^3 (38 B+45 C) \sec (c+d x)\right ) \, dx\\ &=\frac{a^3 (43 B+45 C) \cos ^2(c+d x) \sin (c+d x)}{60 d}+\frac{a B \cos ^4(c+d x) (a+a \sec (c+d x))^2 \sin (c+d x)}{5 d}+\frac{(7 B+5 C) \cos ^3(c+d x) \left (a^3+a^3 \sec (c+d x)\right ) \sin (c+d x)}{20 d}+\frac{1}{4} \left (a^3 (13 B+15 C)\right ) \int \cos ^2(c+d x) \, dx+\frac{1}{15} \left (a^3 (38 B+45 C)\right ) \int \cos (c+d x) \, dx\\ &=\frac{a^3 (38 B+45 C) \sin (c+d x)}{15 d}+\frac{a^3 (13 B+15 C) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{a^3 (43 B+45 C) \cos ^2(c+d x) \sin (c+d x)}{60 d}+\frac{a B \cos ^4(c+d x) (a+a \sec (c+d x))^2 \sin (c+d x)}{5 d}+\frac{(7 B+5 C) \cos ^3(c+d x) \left (a^3+a^3 \sec (c+d x)\right ) \sin (c+d x)}{20 d}+\frac{1}{8} \left (a^3 (13 B+15 C)\right ) \int 1 \, dx\\ &=\frac{1}{8} a^3 (13 B+15 C) x+\frac{a^3 (38 B+45 C) \sin (c+d x)}{15 d}+\frac{a^3 (13 B+15 C) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{a^3 (43 B+45 C) \cos ^2(c+d x) \sin (c+d x)}{60 d}+\frac{a B \cos ^4(c+d x) (a+a \sec (c+d x))^2 \sin (c+d x)}{5 d}+\frac{(7 B+5 C) \cos ^3(c+d x) \left (a^3+a^3 \sec (c+d x)\right ) \sin (c+d x)}{20 d}\\ \end{align*}
Mathematica [A] time = 0.429534, size = 108, normalized size = 0.61 \[ \frac{a^3 (60 (23 B+26 C) \sin (c+d x)+480 (B+C) \sin (2 (c+d x))+170 B \sin (3 (c+d x))+45 B \sin (4 (c+d x))+6 B \sin (5 (c+d x))+780 B c+780 B d x+120 C \sin (3 (c+d x))+15 C \sin (4 (c+d x))+900 C d x)}{480 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.104, size = 223, normalized size = 1.3 \begin{align*}{\frac{1}{d} \left ({\frac{B{a}^{3}\sin \left ( dx+c \right ) }{5} \left ({\frac{8}{3}}+ \left ( \cos \left ( dx+c \right ) \right ) ^{4}+{\frac{4\, \left ( \cos \left ( dx+c \right ) \right ) ^{2}}{3}} \right ) }+{a}^{3}C \left ({\frac{\sin \left ( dx+c \right ) }{4} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{3}+{\frac{3\,\cos \left ( dx+c \right ) }{2}} \right ) }+{\frac{3\,dx}{8}}+{\frac{3\,c}{8}} \right ) +3\,B{a}^{3} \left ( 1/4\, \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{3}+3/2\,\cos \left ( dx+c \right ) \right ) \sin \left ( dx+c \right ) +3/8\,dx+3/8\,c \right ) +{a}^{3}C \left ( 2+ \left ( \cos \left ( dx+c \right ) \right ) ^{2} \right ) \sin \left ( dx+c \right ) +B{a}^{3} \left ( 2+ \left ( \cos \left ( dx+c \right ) \right ) ^{2} \right ) \sin \left ( dx+c \right ) +3\,{a}^{3}C \left ( 1/2\,\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) +1/2\,dx+c/2 \right ) +B{a}^{3} \left ({\frac{\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{2}}+{\frac{dx}{2}}+{\frac{c}{2}} \right ) +{a}^{3}C\sin \left ( dx+c \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.94315, size = 288, normalized size = 1.64 \begin{align*} \frac{32 \,{\left (3 \, \sin \left (d x + c\right )^{5} - 10 \, \sin \left (d x + c\right )^{3} + 15 \, \sin \left (d x + c\right )\right )} B a^{3} - 480 \,{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} B a^{3} + 45 \,{\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} B a^{3} + 120 \,{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} B a^{3} - 480 \,{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} C a^{3} + 15 \,{\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} C a^{3} + 360 \,{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} C a^{3} + 480 \, C a^{3} \sin \left (d x + c\right )}{480 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.500791, size = 278, normalized size = 1.58 \begin{align*} \frac{15 \,{\left (13 \, B + 15 \, C\right )} a^{3} d x +{\left (24 \, B a^{3} \cos \left (d x + c\right )^{4} + 30 \,{\left (3 \, B + C\right )} a^{3} \cos \left (d x + c\right )^{3} + 8 \,{\left (19 \, B + 15 \, C\right )} a^{3} \cos \left (d x + c\right )^{2} + 15 \,{\left (13 \, B + 15 \, C\right )} a^{3} \cos \left (d x + c\right ) + 8 \,{\left (38 \, B + 45 \, C\right )} a^{3}\right )} \sin \left (d x + c\right )}{120 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.20903, size = 284, normalized size = 1.61 \begin{align*} \frac{15 \,{\left (13 \, B a^{3} + 15 \, C a^{3}\right )}{\left (d x + c\right )} + \frac{2 \,{\left (195 \, B a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{9} + 225 \, C a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{9} + 910 \, B a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 1050 \, C a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 1664 \, B a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 1920 \, C a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 1330 \, B a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 1830 \, C a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 765 \, B a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 735 \, C a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right )}^{5}}}{120 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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